MIDACO 6.0 (www.midaco-solver.com) ---------------------------------- LICENSE-KEY: ************************************************************ ---------------------------------------- | OBJECTIVES 1 | PARALLEL 1 | |--------------------------------------| | N 11 | MAXEVAL 999999999 | | NI 8 | MAXTIME 86400 | | M 7 | PRINTEVAL 50000 | | ME 3 | SAVE2FILE 1 | |--------------------------------------| | PARAM[ 1] 2.0000000e+00 RANDOM-SEED | | PARAM[ 2] -9.4347050e-01 FSTOP | ---------------------------------------- [ EVAL, TIME] OBJECTIVE FUNCTION VALUE VIOLATION OF G(X) ------------------------------------------------------------------------------ [ 1, 0] F(X): -0.00000000 VIO: 3.000000 [ 50000, 1] F(X): -0.76070906 VIO: 0.000000 [ 100000, 3] F(X): -0.77246048 VIO: 0.000000 [ 150000, 4] F(X): -0.93165480 VIO: 0.000000 [ 200000, 5] F(X): -0.93165480 VIO: 0.000000 [ 250000, 6] F(X): -0.93165480 VIO: 0.000000 [ 300000, 7] F(X): -0.93165480 VIO: 0.000000 [ 350000, 8] F(X): -0.93165480 VIO: 0.000000 [ 376607, 9] F(X): -0.94347720 VIO: 0.000000 OPTIMIZATION FINISHED ---> FSTOP REACHED BEST SOLUTION FOUND BY MIDACO -------------------------------------------- EVAL: 376607, TIME: 9.00, IFLAG: 7 -------------------------------------------- f[0] = -0.943477202871240 -------------------------------------------- VIOLATION OF G(X) 0.000000000000 -------------------------------------------- g[ 0] = -0.00028917 (EQUALITY CONSTR) g[ 1] = -0.00057126 (EQUALITY CONSTR) g[ 2] = 0.00030145 (EQUALITY CONSTR) g[ 3] = 1.00000000 (IN-EQUAL CONSTR) g[ 4] = 1.00000000 (IN-EQUAL CONSTR) g[ 5] = 0.00000000 (IN-EQUAL CONSTR) g[ 6] = 0.00000000 (IN-EQUAL CONSTR) -------------------------------------------- BOUNDS-PROFIL x[ 0] = 0.970008673701426; # ____________________x x[ 1] = 0.992504283233900; # ____________________x x[ 2] = 0.979993970026703; # ____________________x x[ 3] = 0.000000000000000; # XL___________________ x[ 4] = 1.000000000000000; # ___________________XU x[ 5] = 1.000000000000000; # ___________________XU x[ 6] = 1.000000000000000; # ___________________XU x[ 7] = 0.000000000000000; # XL___________________ x[ 8] = 1.000000000000000; # ___________________XU x[ 9] = 1.000000000000000; # ___________________XU x[ 10] = 1.000000000000000; # ___________________XU