MIDACO 6.0    (www.midaco-solver.com)
 -------------------------------------

 LICENSE-KEY:  MIDACO_LIMITED_VERSION___[CREATIVE_COMMONS_BY-NC-ND_LICENSE]

 ----------------------------------------
 | OBJECTIVES    2 | PARALLEL         1 |
 |--------------------------------------|
 | N             1 | MAXEVAL     100000 |
 | NI            0 | MAXTIME      86400 |
 | M             0 | PRINTEVAL    10000 |
 | ME            0 | SAVE2FILE        1 |
 |--------------------------------------|
 | PARAMETER:    All by default (0)     |
 ----------------------------------------

 [     EVAL,    TIME]   MULTI-OBJECTIVE PROGRESS   VIOLATION OF G(X)
 -------------------------------------------------------------------   [PARETO]
 [        1,       0]   PRO:        105.00000000   VIO:     0.000000   [     1]
 [    10000,       0]   PRO:        -67.39448492   VIO:     0.000000   [   248]
 [    20000,       1]   PRO:        -95.81344549   VIO:     0.000000   [   340]
 [    30000,       1]   PRO:       -116.72297278   VIO:     0.000000   [   363]
 [    40000,       2]   PRO:       -155.72788100   VIO:     0.000000   [   389]
 [    50000,       2]   PRO:       -171.09668602   VIO:     0.000000   [   419]
 [    60000,       3]   PRO:       -201.37715921   VIO:     0.000000   [   429]
 [    70000,       3]   PRO:       -216.88236000   VIO:     0.000000   [   435]
 [    80000,       4]   PRO:       -231.63858192   VIO:     0.000000   [   435]
 [    90000,       4]   PRO:       -234.72713419   VIO:     0.000000   [   448]
 [   100000,       5]   PRO:       -234.72713419   VIO:     0.000000   [   453]

 OPTIMIZATION FINISHED  --->  MAXEVAL REACHED


         BEST SOLUTION FOUND BY MIDACO
 --------------------------------------------
 EVAL:    100000,  TIME:       5,  IFLAG:   1 
 --------------------------------------------
 PROGRESS                -234.727134193929060 
 --------------------------------------------
 NUMBER OF PARETO POINTS                  453
 --------------------------------------------
 f(   1) =                  0.001040347572856 
 f(   2) =                  0.997920387177361 
 --------------------------------------------         BOUNDS-PROFIL    
 x(   1) =                 4.001040347572856;  %  ____________x________